x^2+2x+11=4

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Solution for x^2+2x+11=4 equation:


Simplifying
x2 + 2x + 11 = 4

Reorder the terms:
11 + 2x + x2 = 4

Solving
11 + 2x + x2 = 4

Solving for variable 'x'.

Reorder the terms:
11 + -4 + 2x + x2 = 4 + -4

Combine like terms: 11 + -4 = 7
7 + 2x + x2 = 4 + -4

Combine like terms: 4 + -4 = 0
7 + 2x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-7' to each side of the equation.
7 + 2x + -7 + x2 = 0 + -7

Reorder the terms:
7 + -7 + 2x + x2 = 0 + -7

Combine like terms: 7 + -7 = 0
0 + 2x + x2 = 0 + -7
2x + x2 = 0 + -7

Combine like terms: 0 + -7 = -7
2x + x2 = -7

The x term is 2x.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2x + 1 + x2 = -7 + 1

Reorder the terms:
1 + 2x + x2 = -7 + 1

Combine like terms: -7 + 1 = -6
1 + 2x + x2 = -6

Factor a perfect square on the left side:
(x + 1)(x + 1) = -6

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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